Let \(a\) be an integer and \(p\) a prime number such that \(x^p-a\) is reducible in \(\mathbb {Q}[x]\). Prove that \(x^p-a\) has root in \(\mathbb {Q}\).
Question
Math 6310 • Algebra
Spring 2017 • Question 9
Question
Spring 2017 • Question 9
Let \(a\) be an integer and \(p\) a prime number such that \(x^p-a\) is reducible in \(\mathbb {Q}[x]\). Prove that \(x^p-a\) has root in \(\mathbb {Q}\).