Let \(G\) be a group of order \(p^3\), where \(p\) is a prime. Suppose \(G\) is not abelian. Show that the center \(Z\) of \(G\) is isomorphic to \(\mathbb {Z}/(p)\) and that \(G/Z\cong \mathbb {Z}/(p)\times \mathbb {Z}/(p)\).
Question
Math 6310 • Algebra
Spring 2014 • Question 1