Let \(V\) be a finite-dimensional vector space over a field \(k\), and let \(A\) and \(B\) be diagonalizable linear operators on \(V\) such that \(AB=BA\). Prove that \(A\) and \(B\) are simultaneously diagonalizable; i.e. that there is a basis for \(V\) consisting of eigenvectors of both \(A\) and \(B\).
Question
Math 6310 • Algebra
Fall 2004 • Question 3