Suppose \(K\) is a field of prime order and \(E\) is the algebraic closure of \(K\). If \(F\) is
any subfield of \(E\), prove that the multiplicative group of \(F\) is periodic, i.e.,
every element of the multiplicative group has finite order.
Suppose \(F\) is a field whose multiplicative group is periodic. Prove that for
some prime \(p\), \(F\) is isomorphic to a subfield of the algebraic closure of the
field of order \(p\).