Let \((X,\mathfrak M,\mu )\) be a positive measure space, and let \(f\ge 0\) be a measurable function on \(X\). Define \(g(t)=\mu (\{x:f(x)\ge t\})\). Show that \[ \int _X f(x)\,d\mu (x)=\int _0^\infty g(t)\,dt. \]
Question
Math 6210 • Real Analysis
2004 • Question 4