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Question

Math 6210 • Real Analysis

Fall 2016 • Question 10

The Bernoulli numbers \(B_k\) are defined in terms of the Laurent series \[ \frac {1}{e^z-1} =\frac 1z-\frac 12+\sum _{k=1}^{\infty }(-1)^{k-1}\frac {B_k}{(2k)!}z^{2k-1}. \]

(a) Find the Laurent series of \(\cot \pi z\) in terms of the Bernoulli numbers.

(b) Using (a) and the fact on partial fractions \[ \pi \cot \pi z=\frac 1z+\sum _{n=1}^{\infty }\frac {2z}{z^2-n^2} \] to prove \[ \sum _{n=1}^{\infty }\frac {1}{n^{2k}} =2^{2k-1}\frac {B_k}{(2k)!}\pi ^{2k} \] for any positive integer \(k\).

Raw LaTeX

The Bernoulli numbers \(B_k\) are defined in terms of the Laurent
series
\[
\frac{1}{e^z-1}
=\frac1z-\frac12+\sum_{k=1}^{\infty}(-1)^{k-1}\frac{B_k}{(2k)!}z^{2k-1}.
\]

(a) Find the Laurent series of \(\cot \pi z\) in terms of the Bernoulli
numbers.

(b) Using (a) and the fact on partial fractions
\[
\pi\cot\pi z=\frac1z+\sum_{n=1}^{\infty}\frac{2z}{z^2-n^2}
\]
to prove
\[
\sum_{n=1}^{\infty}\frac{1}{n^{2k}}
=2^{2k-1}\frac{B_k}{(2k)!}\pi^{2k}
\]
for any positive integer \(k\).