For \(f:\mathbb R\to \mathbb R\) and \(y\in \mathbb R\), define \(\tau _y f(x)=f(x-y)\) for \(x\in \mathbb R\). Assume that \(\mathbb R\) is equipped with the Lebesgue measure. For \(f\in L^1(\mathbb R)\), show that the map \(\mathbb R\to L^1(\mathbb R)\) defined by \(y\mapsto \tau _y f\) is uniformly continuous.
Question
Math 6210 • Real Analysis
Fall 2016 • Question 5