Show that the parallelogram law fails for \(L^1([0,1])\) so it is not a Hilbert space.
Hint: Use \(f=\chi _{[0,1/2]}\) and \(g=\chi _{[1/2,1]}\).
Complex Analysis
Question
2002 • Question 5
Show that the parallelogram law fails for \(L^1([0,1])\) so it is not a Hilbert space.
Hint: Use \(f=\chi _{[0,1/2]}\) and \(g=\chi _{[1/2,1]}\).
Complex Analysis