Let \(\gamma \) be a closed path in \(\mathbb C\setminus [0,1]\). Show that \[ \int _\gamma \frac {1}{z(1-z)}\,dz=0. \]
Question
Math 6210 • Real Analysis
2000 • Question 8
Question
2000 • Question 8
Let \(\gamma \) be a closed path in \(\mathbb C\setminus [0,1]\). Show that \[ \int _\gamma \frac {1}{z(1-z)}\,dz=0. \]