Let \(f\) be a non-vanishing holomorphic function defined in a neighborhood of the closed unit disc \(\overline U\) such that \(|f(z)|=1\) if \(|z|=1\). Show that \(f\) is constant.
Question
Math 6210 • Real Analysis
1999 • Question 8
Question
1999 • Question 8
Let \(f\) be a non-vanishing holomorphic function defined in a neighborhood of the closed unit disc \(\overline U\) such that \(|f(z)|=1\) if \(|z|=1\). Show that \(f\) is constant.