Let \(X\geq 0\), \(\mathbb {E} X^2<\infty \), and \(0\leq a<\mathbb {E} X\). Apply the Cauchy–Schwarz inequality to prove that \[ \mathbb {P}(X>a)\geq \frac {(\mathbb {E} X-a)^2}{\mathbb {E} X^2}. \]
Question
Math 6010 • Linear Models
Spring 2011 • Question 9