Suppose \(\{X_n\}_{n=1}^{\infty }\) are i.i.d. exponential random variables with mean one; that is, \(\mathbb {P}\{X_n>x\}=e^{-x}\) for all \(x>0\). Prove that \[ \mathbb {P}\left \{\limsup _{n\to \infty }\frac {X_n}{\log n}=1\right \}=1. \]
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Math 6010 • Linear Models
Fall 2016 • Question 6