Bernstein-Bezier Form Let \(T\) be a non-degenerate triangle with vertices \(V_1\), \(V_2\), and \(V_3\). The barycentric coordinates \(b_1\), \(b_2\), and \(b_3\) of a point \(x\in \mathbb {R}^2\) with respect to \(T\) are defined by \[ x=\sum _{i=1}^3 b_i V_i \qquad \text {where}\qquad \sum _{i=1}^3 b_i=1. \tag {6} \] A polynomial \(p\) of degree \(d\) can be written uniquely in its Bernstein-Bezier form as \[ p(x)=\sum _{i+j+k=d}\frac {d!}{i!j!k!}c_{ijk}b_1^i b_2^j b_3^k. \tag {7} \] Assuming you know the coefficients \(c_{ijk}\) of \(p\) as a polynomial of degree \(d\), show how to write \(p\) as a polynomial of degree \(d+1\) in Bernstein-Bezier form. What are the coefficients of \(p\) if \(p(x)=1\)?
Question
Math 6610 • Analysis of Numerical Methods I
Winter 2004 • Question 4