Show that \(\mathbb {R}P^3\) is not homotopy equivalent to \(\mathbb {R}P^2\vee S^3\).
Question
Math 6510 • Differentiable Manifolds
Winter 2004 • Question 15
Question
Winter 2004 • Question 15
Show that \(\mathbb {R}P^3\) is not homotopy equivalent to \(\mathbb {R}P^2\vee S^3\).