Recall that if \(X\) is a topological space its suspension \(SX\) is the product \(X\times [0,1]\) with both \(X\times \{0\}\) and \(X\times \{1\}\) collapsed to points. Show that \(\operatorname {H}_{n+1}(SX)=\operatorname {H}_n(X)\) for \(n\ge 0\).
Question
Math 6510 • Differentiable Manifolds
Spring 2020 • Question 9