Suppose \(X\) and \(Y\) are cell complexes and that \(A\subseteq X\) is a subcomplex. Let \(f:A\to Y\) be continuous and let \(Y\sqcup _f X\) be \(Y\) with \(X\) attached along \(A\) via \(f\). Prove that \(Y\sqcup _f X\) is homotopy equivalent to a cell complex.
Question
Math 6510 • Differentiable Manifolds
Spring 2018 • Question 7