Define \(\phi :\mathbb {R}^2\to \mathbb {R}^2\backslash \{0\}\) by \(\phi (x,y)=(e^x\cos y,e^x\sin y)\). Let \(\omega \) be a 1-form on \(\mathbb {R}^2\backslash \{0\}\) such that \(dy=\phi ^*\omega \). Show that \(\omega \) is closed but not exact on \(\mathbb {R}^2\backslash \{0\}\).
Question
Math 6510 • Differentiable Manifolds
Fall 2014 • Question 2