Without resorting to the DeRham Theorem, prove that \(H^2(\mathbb {R}^2)=0\) (where \(H^2(\mathbb {R}^2)\) denotes the 2 dimesional DeRham cohomology).
Question
Math 6510 • Differentiable Manifolds
Fall 2000 • Question 3
Question
Fall 2000 • Question 3
Without resorting to the DeRham Theorem, prove that \(H^2(\mathbb {R}^2)=0\) (where \(H^2(\mathbb {R}^2)\) denotes the 2 dimesional DeRham cohomology).