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Question

Math 6510 • Differentiable Manifolds

Fall 2000 • Question 3

Without resorting to the DeRham Theorem, prove that \(H^2(\mathbb {R}^2)=0\) (where \(H^2(\mathbb {R}^2)\) denotes the 2 dimesional DeRham cohomology).

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Without resorting to the DeRham Theorem, prove that
\(H^2(\mathbb{R}^2)=0\) (where \(H^2(\mathbb{R}^2)\) denotes the 2 dimesional DeRham
cohomology).