Let \(A\) be an \(n\times n\) real matrix whose eigenvalues \(\lambda _i\) satisfy \(\Re \lambda _i<0\) for all \(i=1,\ldots ,n\). Consider the initial value problem for \(x_0\in \mathbb {R}^n\), \begin{equation} \begin {cases} \dfrac {dx}{dt}=Ax+\dfrac {t\norm {x}^3}{1+t}v,\\ x(0)=x_0 \end {cases} \tag {2} \end{equation} where \(v\in \mathbb {R}^n\) is a unit vector.
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Show that if \(\lvert x_0\rvert \) is small enough, there is a bounded solution to (2) that exists for all time.
[Hint: Suppose \(g(t)\) and \(u(t)\) are nonnegative functions and \(c_0\ge 0\) is a constant that satisfy \(u(t)\le c_0+\int _0^t g(s)u(s)\dd s\) for all \(t\ge 0\). Then Gronwall’s Inequality implies \[ u(t)\le c_0\exp \left (\int _0^t g(s)\dd s\right ) \] for all \(t\ge 0\).]
- Let \(z(t)=0\) for all \(t\) be the zero solution to (2) . Define what it means for \(z\) to be Lyapunov Stable (some authors call this notion stable .) Show that \(z\) is Lyapunov stable for this equation.