Consider a linear chain of \(2N\) atoms consisting of two different masses \(m\), \(M\) \(M>m\), placed alternately. The atoms are equally spaced with lattice spacing \(a\) with nearest neighbor interactions represented by Hookean springs with spring constant \(\beta \). Label the light atoms by even integers \(2n\), \(n=0,\ldots ,N-1\) and the heavy atoms by odd integers \(2n-1\), \(n=1,\ldots ,N\). Denoting their displacements from equilibrium by the variables \(U_{2n}\) and \(V_{2n-1}\) respectively, Newton’s law of motion gives \[ \begin {aligned} m\ddot {U}_{2n} &= \beta [V_{2n-1}+V_{2n+1}-2U_{2n}],\\ M\ddot {V}_{2n-1} &= \beta [U_{2n}+U_{2n-2}-2V_{2n-1}] \end {aligned} \] Assume periodic boundary conditions \(U_0=U_{2N}\) and \(V_1=V_{2N+1}\).
- Sketch the configuration of atoms and briefly explain how the dynamical equations arise from Newton’s law of motion.
- Assuming a solution of the form \[ U_{2n}=\Phi e^{2inka}e^{-iwt},\qquad V_{2n+1}=\Psi e^{i(2n+1)ka}e^{-iwt}, \] derive an eigenvalue equation for the amplitudes \((\Phi ,\Psi )\) and determine the eigenvalues.
- Using part (b), show that there are two branches of solution and determine the speed \(w/k\) on the two branches for small \(k\).