Skip to content

Question

Math 6410 • ODE

Fall 2017 • Question 8

Consider the problem of a thin layer of paint of thickness \(h(x,t)\) and speed \(u(x,y,t)\) flowing down a wall. The paint is assumed to be uniform in the \(z\)-direction. The balance between gravity and viscosity (fluid friction) means that the velocity satisfies the equation \[ \frac {\partial ^2u}{\partial y^2}=-c, \] where \(c\) is a positive constant. This is supplemented by the boundary conditions \[ u(x,0,t)=0,\qquad \left .\frac {\partial u(x,y,t)}{\partial y}\right |_{y=h}=0. \] The density of paint per unit length in the \(x\)-direction is \(\rho _0h(x,t)\) where \(\rho _0\) is a constant, and the corresponding flux is \[ q(x,t)=\rho _0\int _0^h u(x,y,t)d y. \]

  1. Sketch a figure illustrating the physical problem.
  2. Using conservation of paint, and solving for \(u(x,y,t)\) in terms of \(h(x,t)\) and \(y\), derive the following PDE for the thickness \(h\): \[ \frac {\partial h}{\partial t}+ch^2\frac {\partial h}{\partial x}=0. \]
  3. Set \(c=1\). Show that the characteristics are straight lines and that the Rankine-Hugoniot condition on a shock \(x=S(t)\) is \[ \frac {dS}{dt}=\frac {[h^3/3]^+_-}{[h]^+_-}. \]
  4. A stripe of paint is applied at \(t=0\) so that \[ h(x,0)= \begin {cases} 0, & x<0\text { or }x>1,\\ 1, & 0<x<1. \end {cases} \] Show that, for small enough \(t\), \[ h= \begin {cases} 0, & x<0,\\ (x/t)^{1/2}, & 0<x<t,\\ 1, & t<x<S(t),\\ 0, & S(t)<x, \end {cases} \] where the shock is \(x=S(t)=1+t/3\). Explain why this solution changes at \(t=3/2\), and show that thereafter \[ \frac {dS}{dt}=\frac {S}{3t}. \]

Raw LaTeX

Consider the problem of a thin layer of paint of thickness \(h(x,t)\) and speed
\(u(x,y,t)\) flowing down a wall. The paint is assumed to be uniform in the \(z\)-direction.
The balance between gravity and viscosity (fluid friction) means that the velocity
satisfies the equation
\[
  \frac{\partial^2u}{\partial y^2}=-c,
\]
where \(c\) is a positive constant. This is supplemented by the boundary conditions
\[
  u(x,0,t)=0,\qquad
  \left.\frac{\partial u(x,y,t)}{\partial y}\right|_{y=h}=0.
\]
The density of paint per unit length in the \(x\)-direction is \(\rho_0h(x,t)\) where
\(\rho_0\) is a constant, and the corresponding flux is
\[
  q(x,t)=\rho_0\int_0^h u(x,y,t)\dd y.
\]
\begin{enumerate}
\item[(a)] Sketch a figure illustrating the physical problem.
\item[(b)] Using conservation of paint, and solving for \(u(x,y,t)\) in terms of
\(h(x,t)\) and \(y\), derive the following PDE for the thickness \(h\):
\[
  \frac{\partial h}{\partial t}+ch^2\frac{\partial h}{\partial x}=0.
\]
\item[(c)] Set \(c=1\). Show that the characteristics are straight lines and that the
Rankine-Hugoniot condition on a shock \(x=S(t)\) is
\[
  \frac{dS}{dt}=\frac{[h^3/3]^+_-}{[h]^+_-}.
\]
\item[(d)] A stripe of paint is applied at \(t=0\) so that
\[
  h(x,0)=
  \begin{cases}
    0, & x<0\text{ or }x>1,\\
    1, & 0<x<1.
  \end{cases}
\]
Show that, for small enough \(t\),
\[
  h=
  \begin{cases}
    0, & x<0,\\
    (x/t)^{1/2}, & 0<x<t,\\
    1, & t<x<S(t),\\
    0, & S(t)<x,
  \end{cases}
\]
where the shock is \(x=S(t)=1+t/3\). Explain why this solution changes at \(t=3/2\),
and show that thereafter
\[
  \frac{dS}{dt}=\frac{S}{3t}.
\]
\end{enumerate}