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Math 6410 • ODE

Fall 2016 • Question 3

Consider the van der Pol equation \[ \ddot {x}+x+\epsilon (x^2-1)\dot {x}=\Gamma \cos (\omega t), \qquad 0<\epsilon \ll 1 \] with \(\Gamma =O(1)\) and \(\omega \ne 1/3,1,3\). Using the method of multiple scales show that the solution is attracted to \[ x(t)=\frac {\Gamma }{1-\omega ^2}\cos \omega t+O(\epsilon ) \] when \(\Gamma ^2\ge 2(1-\omega ^2)^2\) and \[ x(t)=2\left [1-\frac {\Gamma ^2}{2(1-\omega ^2)^2}\right ]^{1/2}\cos t +\frac {\Gamma }{1-\omega ^2}\cos \omega t+O(\epsilon ) \] when \(\Gamma ^2<2(1-\omega ^2)^2\). Explain why this result breaks down when \(\omega =1/3,1,3\).

Raw LaTeX

Consider the van der Pol equation
\[
  \ddot{x}+x+\epsilon(x^2-1)\dot{x}=\Gamma\cos(\omega t),
  \qquad 0<\epsilon\ll1
\]
with \(\Gamma=O(1)\) and \(\omega\ne 1/3,1,3\). Using the method of multiple scales show
that the solution is attracted to
\[
  x(t)=\frac{\Gamma}{1-\omega^2}\cos\omega t+O(\epsilon)
\]
when \(\Gamma^2\ge2(1-\omega^2)^2\) and
\[
  x(t)=2\left[1-\frac{\Gamma^2}{2(1-\omega^2)^2}\right]^{1/2}\cos t
  +\frac{\Gamma}{1-\omega^2}\cos\omega t+O(\epsilon)
\]
when \(\Gamma^2<2(1-\omega^2)^2\). Explain why this result breaks down when
\(\omega=1/3,1,3\).