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Math 6410 • ODE

Fall 2015 • Question 6

Consider the problem of a thin layer of paint of thickness \(h(x,t)\) and speed \(u(x,y,t)\) flowing down a wall, see Fig. 1. The paint is assumed to be uniform in the \(z\)-direction. The balance between gravity and viscosity (fluid friction) means that the velocity satisfies the equation \[ \frac{\partial^2u}{\partial y^2}=-c, \] where \(c\) is a positive constant. This is supplemented by the boundary conditions \[ u(x,0,t)=0,\qquad \left.\frac{\partial u(x,y,t)}{\partial y}\right|_{y=h}=0. \] The density of paint per unit length in the \(x\)-direction is \(\rho_0h(x,t)\) where \(\rho_0\) is a constant, and the corresponding flux is \[ q(x,t)=\rho_0\int_0^h u(x,y,t)\,d y. \] **(a)** Using conservation of paint, and solving for \(u(x,y,t)\) in terms of \(h(x,t)\) and \(y\), derive the following PDE for the thickness \(h\): \[ \frac{\partial h}{\partial t}+ch^2\frac{\partial h}{\partial x}=0. \] **(b)** Set \(c=1\). Show that the characteristics are straight lines and that the Rankine-Hugoniot condition on a shock \(x=S(t)\) is \[ \frac{dS}{dt}=\frac{[h^3/3]_-^+}{[h]_-^+}. \] A stripe of paint is applied at \(t=0\) so that \[ h(x,0)= \begin{cases} 0, & x<0\text{ or }x>1,\\ 1, & 0 **Diagram:** See the accessible exam PDF linked above.

Raw LaTeX

Consider the problem of a thin layer of paint of thickness \(h(x,t)\) and speed
\(u(x,y,t)\) flowing down a wall, see Fig. 1. The paint is assumed to be uniform in
the \(z\)-direction. The balance between gravity and viscosity (fluid friction) means
that the velocity satisfies the equation
\[
  \frac{\partial^2u}{\partial y^2}=-c,
\]
where \(c\) is a positive constant. This is supplemented by the boundary conditions
\[
  u(x,0,t)=0,\qquad
  \left.\frac{\partial u(x,y,t)}{\partial y}\right|_{y=h}=0.
\]
The density of paint per unit length in the \(x\)-direction is \(\rho_0h(x,t)\) where
\(\rho_0\) is a constant, and the corresponding flux is
\[
  q(x,t)=\rho_0\int_0^h u(x,y,t)\dd y.
\]
\begin{enumerate}
\item[(a)] Using conservation of paint, and solving for \(u(x,y,t)\) in terms of
\(h(x,t)\) and \(y\), derive the following PDE for the thickness \(h\):
\[
  \frac{\partial h}{\partial t}+ch^2\frac{\partial h}{\partial x}=0.
\]
\item[(b)] Set \(c=1\). Show that the characteristics are straight lines and that the
Rankine-Hugoniot condition on a shock \(x=S(t)\) is
\[
  \frac{dS}{dt}=\frac{[h^3/3]_-^+}{[h]_-^+}.
\]
A stripe of paint is applied at \(t=0\) so that
\[
  h(x,0)=
  \begin{cases}
    0, & x<0\text{ or }x>1,\\
    1, & 0<x<1.
  \end{cases}
\]
Show that, for small enough \(t\),
\[
  h=
  \begin{cases}
    0, & x<0,\\
    (x/t)^{1/2}, & 0<x<t,\\
    1, & t<x<S(t),\\
    0, & S(t)<x,
  \end{cases}
\]
where the shock is \(x=S(t)=1+t/3\). Explain why this solution changes at \(t=3/2\),
and show that thereafter
\[
  \frac{dS}{dt}=\frac{S}{3t}.
\]
\end{enumerate}

\begin{center}
\begin{tikzpicture}[scale=0.88,>=Latex,line cap=round,line join=round]
  \begin{scope}
    \draw[->] (0,0) -- (0,-3.4) node[below] {\(x\)};
    \draw[->] (0,0) -- (2.1,0) node[right] {\(y\)};
    \draw[thick] (0,0) -- (0,-3.0);
    \node[left] at (-0.15,-1.65) {wall};
    \draw[thick] (1.25,0) .. controls (1.25,-0.65) and (1.55,-1.2) .. (1.43,-1.65)
      .. controls (1.25,-2.2) and (1.35,-2.6) .. (1.35,-3.0);
    \node[right,align=left] at (1.5,-0.85) {surface of\\paint layer};
    \draw[->] (0,-1.5) -- (1.28,-1.5);
    \node[below] at (0.72,-1.5) {\(h(x,t)\)};
    \draw (0,-2.1) -- (1.28,-2.1);
    \draw[->] (0.35,-2.1) -- (0.35,-2.65);
    \draw[->] (0.72,-2.1) -- (0.72,-2.78);
    \draw[->] (1.05,-2.1) -- (1.05,-2.75);
    \node at (0.76,-2.95) {\(u(x,y,t)\)};
  \end{scope}
  \begin{scope}[xshift=5.2cm,yshift=-0.1cm]
    \draw[thick] (0,0) rectangle (1.1,-2.55);
    \draw[dashed] (0.55,0) -- (0.55,-2.55);
    \draw[->] (0.25,0.35) -- (0.25,-0.35);
    \node[above] at (0.25,0.35) {\(q(x,t)\)};
    \draw[->] (0.25,-2.2) -- (0.25,-2.75);
    \node[below] at (0.25,-2.75) {\(q(x+\Delta x,t)\)};
    \node[left] at (-0.15,-0.2) {\(x\)};
    \node[left] at (-0.15,-2.35) {\(x+\Delta x\)};
    \draw[<->] (0.65,0.18) -- (1.05,0.18);
    \node[above] at (0.86,0.18) {\(\Delta h\)};
  \end{scope}
\end{tikzpicture}
\end{center}