Let \(f\) be a real-valued and twice continuously differentiable on an interval \([a,b]\). Let \(\hat {x}\) be a simple zero of \(f\), i.e. \(f'(\hat {x})\ne 0\). Use the Banach Fixed Point Theorem to show that Newton’s method, defined by \[ x_{n+1}=x_n-\frac {f(x_n)}{f'(x_n)} \] converges to \(\hat {x}\) for any \(x_0\) sufficiently close to \(\hat {x}\).
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Math 6420 • PDE
Spring 2017 • Question 2