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Question

Math 6420 • PDE

Spring 2016 • Question 1

Let \(X\) be a Banach space, let \(z\in X\) with \(z\ne 0\), and let \(f\in X'\) with \(f\ne 0\). Consider the linear operator \(T:X\to X\) defined for \(x\in X\) by \[ Tx=f(x)z. \]

  1. Briefly explain why \(T\) is compact.
  2. Use Neumann series to give a condition on \(f\) and \(z\) that ensures the equation \(x+Tx=y\) admits a unique solution \(x\) for all \(y\in X\).
  3. Use the Fredholm alternative to find a condition on \(f\) and \(z\) that ensures the equation \(x+Tx=y\) admits a unique solution \(x\) for all \(y\in X\).

Raw LaTeX

Let \(X\) be a Banach space, let \(z\in X\) with \(z\ne0\), and let \(f\in X'\) with
\(f\ne0\). Consider the linear operator \(T:X\to X\) defined for \(x\in X\) by
\[
  Tx=f(x)z.
\]
\begin{enumerate}
\item[(a)] Briefly explain why \(T\) is compact.

\item[(b)] Use \textbf{Neumann series} to give a condition on \(f\) and \(z\) that ensures the
equation \(x+Tx=y\) admits a unique solution \(x\) for all \(y\in X\).

\item[(c)] Use the \textbf{Fredholm alternative} to find a condition on \(f\) and \(z\) that
ensures the equation \(x+Tx=y\) admits a unique solution \(x\) for all \(y\in X\).
\end{enumerate}