Show that if \(f\) is holomorphic on an open neighborhood of \(\overline {\mathbb {D}}\) and \(|f(z)|=1\) on \(|z|=1\) then \(f\) is a rational function.
Question
Math 6220 • Complex Analysis
Fall 2022 • Question 2
Question
Fall 2022 • Question 2
Show that if \(f\) is holomorphic on an open neighborhood of \(\overline {\mathbb {D}}\) and \(|f(z)|=1\) on \(|z|=1\) then \(f\) is a rational function.