Evaluate the integral \[ I=\int _0^\infty \frac {x^\alpha \,dx}{(x^2+1)} \] (where \(\alpha \) is a parameter, such that the integral converges).
Question
Math 6420 • PDE
Fall 2009 • Question 9
Question
Fall 2009 • Question 9
Evaluate the integral \[ I=\int _0^\infty \frac {x^\alpha \,dx}{(x^2+1)} \] (where \(\alpha \) is a parameter, such that the integral converges).