Show that a test function \(\psi (x)\) is of the form \(\psi =(x\phi )'\) where \(\phi \) is a test function if and
only if \[ \int _{-\infty }^{\infty }\psi (x)\,dx=0 \quad \text {and}\quad \int _0^{\infty }\psi (x)\,dx=0. \]
Solve the following equation in the sense of distribution: \[ x^2\frac {d\phi }{dx}=0. \]