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Question

Math 6420 • PDE

Fall 2005 • Question 10

Suppose that \(\psi _+(z)\) is analytic on the upper half plane and \(\psi _-(z)\) is analytic on the lower half plane such that on the real axis \[ \psi _+(x)-\psi _-(x)=f(x) \] Assuming that the integrable function \(f(x)\) can be analytically extended in a neighborhood of the real axis, show that a solution to this problem is given by the Cauchy integral \[ \Psi (z)=\frac {1}{2\pi i}\int _{-\infty }^{\infty }\frac {f(\xi )}{\xi -z}\,d\xi \] with \(\psi _\pm (x)=\lim _{\epsilon \to 0+}\Psi (x\pm i\epsilon )\). Hence, establish that \[ \psi _+(x)+\psi _-(x)=\frac {1}{\pi i}\operatorname {PV} \int _{-\infty }^{\infty }\frac {f(\xi )}{\xi -x}\,d\xi \] where \(\operatorname {PV}\) denotes the principal value.

Raw LaTeX

Suppose that \(\psi_+(z)\) is analytic on the upper half plane and \(\psi_-(z)\) is
analytic on the lower half plane such that on the real axis
\[
  \psi_+(x)-\psi_-(x)=f(x)
\]
Assuming that the integrable function \(f(x)\) can be analytically extended in a neighborhood
of the real axis, show that a solution to this problem is given by the Cauchy integral
\[
  \Psi(z)=\frac{1}{2\pi i}\int_{-\infty}^{\infty}\frac{f(\xi)}{\xi-z}\,d\xi
\]
with \(\psi_\pm(x)=\lim_{\epsilon\to 0+}\Psi(x\pm i\epsilon)\). Hence, establish that
\[
  \psi_+(x)+\psi_-(x)=\frac{1}{\pi i}\operatorname{PV}
  \int_{-\infty}^{\infty}\frac{f(\xi)}{\xi-x}\,d\xi
\]
where \(\operatorname{PV}\) denotes the principal value.