Consider the flow around a thin airfoil of length \(2a\) that is inclined at an angle \(\alpha \) to the \(x\)-axis. Assume that there is uniform flow at \(\infty \) with velocity \(U_x=U\), \(U_y=0\).
- Show that the conformal map \[ z=\frac {ae^{-i\alpha }}{2}\left (\omega +\frac {1}{\omega }\right ) \] maps the unit circle in the \(\omega \)-plane to the airfoil in the \(z\)-plane.
- Consider the complex potential \[ \Gamma (\omega )=\frac {aU}{2}\left (e^{-i\alpha }\omega +\frac {e^{i\alpha }}{\omega }\right ) -\frac {i\gamma }{2\pi }\log \omega . \] Calculate the corresponding potential \(\Omega (z)=\Gamma (\omega (z))\) where \(\omega (z)\) is the inverse of the conformal map in part (a). What does the term in \(\gamma \) represent?
- Calculate \(\Omega '(z)\) and show that it satisfies the correct asymptotic flow. Determine what happens at the end points of the airfoil, and use this to calculate \(\gamma \).