Evaluate the integral \[ I=\int _0^\infty \frac {x^\alpha }{x^2+1}\,dx \] where \(\alpha \) is a parameter, \(-1<\alpha <1\).
Question
Math 6420 • PDE
Fall 1999 • Question 8
Question
Fall 1999 • Question 8
Evaluate the integral \[ I=\int _0^\infty \frac {x^\alpha }{x^2+1}\,dx \] where \(\alpha \) is a parameter, \(-1<\alpha <1\).