Let \(C\) be a closed convex set in a Hilbert space \(H\), and let \(u\) be an arbitrary vector in \(H\). Show that there exists one and only one element in \(C\) which is closest to \(u\).
Question
Math 6420 • PDE
Fall 1999 • Question 4
Question
Fall 1999 • Question 4
Let \(C\) be a closed convex set in a Hilbert space \(H\), and let \(u\) be an arbitrary vector in \(H\). Show that there exists one and only one element in \(C\) which is closest to \(u\).