Consider a 2-dimensional map \((x,y)\to (u,v)\). Explain: If the map is given by an analytic
function [\(u+iv=f(x+iy)\)] and at some point \(z_0=x_0+iy_0\) the derivative \(f'(z_0)\ne 0\), then this map preserves
small shapes in the vicinity of \(z_0\).
Is a square conformally equivalent to a circle?
Explain: A map by analytic function preserves Laplace’s equation.