Integrate
- \[ \int _0^\infty \frac {\sin \alpha x}{x}\,dx, \]
- \[ \int _0^\infty \frac {x^\alpha }{1+x}\,dx, \]
- \[ \int _0^\infty \sin x^2\,dx \]
[Explain the logic (in particular, the choice of contour), but do not worry about getting the exact numbers; \(\alpha \) is a real parameter.]